A particle moves such that its acceleration a is given by a = - b… - Vidyadip

MCQ

A particle moves such that its acceleration $a$ is given by $a = - bx$, where $x$ is the displacement from equilibrium position and b is a constant. The period of oscillation is

A
$2\pi \sqrt b $
✓
$\frac{{2\pi }}{{\sqrt b }}$
C
$\frac{{2\pi }}{b}$
D
$2\sqrt {\frac{\pi }{b}} $

✓

Answer

Correct option: B.

$\frac{{2\pi }}{{\sqrt b }}$

b
(b) In the given case, $\frac{{Displacement}}{{Acceleration}} = \frac{1}{b}$
ime period $T = 2\pi \sqrt {\frac{{Displacement}}{{Acceleration}}} = \frac{{2\pi }}{{\sqrt b }}$

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