MCQ
A particle moves with constant angular velocity in circular path of certain radius and is acted upon by a certain centripetal force $F$. if the angular velocity is kept same but the radius of the path is halved, the new force will be
  • A
    $2F$
  • B
    ${F^2}$
  • $F/2$
  • D
    $F/4$

Answer

Correct option: C.
$F/2$
c
(c) $F = m{\omega ^2}R$ $\therefore$ $F \propto R$ ($m$ and $\omega$ are constant)

If radius of the path is halved, then force will also become half.

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