A particle of mass $m = 1.67 \times 10^{-27}\, kg$ and charge $q = 1.6 \times 10^{-19} \, C$ enters a region of uniform magnetic field of strength $1$ $tesla$ along the direction shown in the figure. the time spent by the particle in the magnetic field is......$ns$
Diffcult
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A milliammeter of range $10\, mA$ has a coil of resistance $1 \,\Omega$. To use it as voltmeter of range $10\, volt$, the resistance that must be connected in series with it, will be ............. $\Omega $
A current $I$ flows around a closed path in the horizontal plane of the circle as shown in the figure. The path consists of eight arcs with alternating radii $r$ and $2r$. Each segment of arc subtends equal angle at the common centre $P.$ The magnetic field produced by current path at point $P$ is
A charge particle $A$ of charge $q = 2\,\, C$ has velocity $v = 100\,\, m/s.$ When it passes through point Aand has velocity in the direction shown. The strength of magnetic field at point $B$ due to this moving charge is.......$\mu T$ $(r = 2\,\, m).$
A particle of specific charge $(q/m)$ is projected from the origin of coordinates with initial velocity $[ui - vj]$. Uniform electric magnetic fields exist in the region along the $+y$ direction, of magnitude $E$ and $B.$ The particle will definitely return to the origin once if
In the hydrogen atom, the electron is making $6.6 \times {10^{15}}\,r.p.s.$ If the radius of the orbit is $0.53 \times {10^{ - 10}}\,metre,$ then magnetic field produced at the centre of the orbit is......$Tesla$
In a circuit for finding the resistance of a galvanometer by half deflection method, a $6\,V$ battery and a high resistance of $11\,k\Omega $ are used. The figure of merit of the galvanometer $60\,\mu A/$ division. In the absence of shunt resistance, the galvanometer produces a deflection of $\theta = 9$ divisions when current flows in the circuit. The value of the shunt resistance that can cause the deflection of $\theta /2 ,$ is closest to .................. $\Omega$
A galvanometer has a resistance of $20\,\Omega$ and reads full-scale when $0.2\, V$ is applied across it. To convert it into a $10\, A$ ammeter, the galvanometer coil should have a
An imaginary north pole of $10\,Am$ is rotating around an infinite long current carrying wire with $30\,revolution/min.$ on circular path. If current in wire is $5\,A$ then workdone in one second in doing so