In an ammeter, $5 \%$ of the main current passes through the galvanometer. If resistance of the galvanometer is G, the resistance of ammeter will be :
  • A$\frac{G}{20}$
  • B $\frac{G}{199}$
  • C$199 \mathrm{G}$
  • D$200 \mathrm{G}$
JEE MAIN 2024, Diffcult
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