at $t=0$
Particle is at $-\frac{A}{2}$ $\&$ moving towards negative extreme.
So. $(\mathrm{x}-3)=6 \sin (4 \pi \mathrm{t}+7 \pi / 6)$
$\mathrm{x}=3+6 \sin (4 \pi \mathrm{t}+7 \pi / 6)$
$(A)\;y= sin\omega t-cos\omega t$
$(B)\;y=sin^3\omega t$
$(C)\;y=5cos\left( {\frac{{3\pi }}{4} - 3\omega t} \right)$
$(D)\;y=1+\omega t+{\omega ^2}{t^2}$
($A$) The amplitude of oscillation in the first case changes by a factor of $\sqrt{\frac{M}{m+M}}$, whereas in the second case it remains unchanged
($B$) The final time period of oscillation in both the cases is same
($C$) The total energy decreases in both the cases
($D$) The instantaneous speed at $x_0$ of the combined masses decreases in both the cases
