A particle starts from a point $P$ at a distance of $A/2$ from the mean position $O$ and travels towards left as shown in the figure. If the time period of $SHM$ , executed about $O$ is $T$ and amplitude $A$ then the equation of motion of particle is
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$\mathrm{x}=\mathrm{A} \sin \left(\omega \mathrm{t}+\frac{\pi}{2}+\frac{\pi}{3}\right)$
$\mathrm{x}=\mathrm{A} \sin \left(\omega \mathrm{t}+\frac{5 \pi}{6}\right)=\mathrm{A} \sin \left(\frac{2 \mathrm{n}}{\mathrm{T}} \mathrm{t}+\frac{5 \mathrm{n}}{6}\right)$
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