MCQ
A pendulum clock keeps correct time at $0°C$. Its mean coefficient of linear expansions is $\alpha /^\circ C$, then the loss in seconds per day by the clock if the temperature rises by $t°C$ is
- A$\frac{{\frac{1}{2}\alpha \,t \times 864000}}{{1 - \frac{{\alpha \,t}}{2}}}$
- ✓$\frac{1}{2}\alpha \,t \times \,86400$
- C$\frac{{\frac{1}{2}\alpha \,t \times 86400}}{{{{\left( {1 - \,\frac{{\alpha \,t}}{2}} \right)}^2}}}$
- D$\frac{{\frac{1}{2}\alpha \,t \times 86400}}{{1 + \frac{{\alpha \,t}}{2}}}$
