A pendulum suspended from the ceiling of a train has a period $T$, when the train is at rest. When the train is accelerating with a uniform acceleration a, the period of oscillation will
Easy
Download our app for free and get started
(b) Initially time period was $T = 2\pi \sqrt {\frac{l}{g}} $.
When train accelerates, the effective value of $g$ becomes $\sqrt {({g^2} + {a^2})} $ which is greater than $g$
Hence, new time period, becomes less than the initial time period.
When train accelerates, the effective value of $g$ becomes $\sqrt {({g^2} + {a^2})} $ which is greater than $g$
Hence, new time period, becomes less than the initial time period.
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A block of mass $m$ is attached to two springs of spring constants $k_1$ and $k_2$ as shown in figure. The block is displaced by $x$ towards right and released. The velocity of the block when it is at $x/2$ will beView Solution
- 2A particle performing $SHM$ is found at its equilibrium at $t = 1\,sec$. and it is found to have a speed of $0.25\,m/s$ at $t = 2\,sec$. If the period of oscillation is $6\,sec$. Calculate amplitude of oscillationView Solution
- 3A particle is executing $SHM$ with amplitude $A,$ time period $T,$ maximum acceleration $a_o$ and maximum velocity $v_0.$ Its starts from mean position at $t=0$ and at time $t,$ it has the displacement $A/2,$ acceleration $a$ and velocity $v$ thenView Solution
- 4A simple pendulum oscillates in air with time period $T$ and amplitude $A$. As the time passesView Solution
- 5A light pointer fixed to one prong of a tuning fork touches a vertical plate. The fork is set vibrating and the plate is allowed to fall freely. If eight oscillations are counted when the plate falls through $10 cm$, the frequency of the tuning fork is .... $Hz$View Solution
- 6Figure shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and the initial position are indicated on the figure. The simple harmonic motion of the $x-$ projection of the radius vector of the rotating particle $P$ isView Solution
- 7View SolutionThis is the position time graph of a mass on spring. What can you say about the velocity and force at the instant indicated by dashed line ? (positive direction is to the right)
- 8The displacement $x$ (in metre) of a particle in, simple harmonic motion is related to time t (in seconds) asView Solution
$x = 0.01\cos \left( {\pi \,t + \frac{\pi }{4}} \right)$
The frequency of the motion will be
- 9View SolutionTwo oscillating systems; a simple pendulum and a vertical spring-mass-system have same time period of motion on the surface of the Earth. If both are taken to the moon, then-
- 10The point $A$ moves with a uniform speed along the circumference of a circle of radius $0.36\, m$ and covers $30^{\circ}$ in $0.1\, s$. The perpendicular projection $'P'$ from $'A'$ on the diameter $MN$ represents the simple harmonic motion of $'P'.$ The restoration force per unit mass when $P$ touches $M$ will be ...... $N$View Solution
