The displacement $x$ (in metre) of a particle in, simple harmonic motion is related to time t (in seconds) as
$x = 0.01\cos \left( {\pi \,t + \frac{\pi }{4}} \right)$
The frequency of the motion will be
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(a) Comparing given equation with standard equation, $x = a\cos \,(\omega t + \phi )$
we get, $a = 0.01$ and $\omega = \pi $
$ \Rightarrow 2\pi n = \pi \Rightarrow n = 0.5\,Hz$
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