A person standing at a distance of $6\,\, m$ from a source of sound receives sound wave in two ways, one directly from the source and other after reflection from a rigid boundary as shown in the figure. The maximum wavelength for which, the person will receive maximum sound intensity, is .... $m$
Diffcult
Download our app for free and get started
For the intensity to be maximum after interference, the path difference between the two waves must be an integral multiple of wavelength.
Hence, $(5+5)-6=n \lambda$
$\Longrightarrow \lambda=\frac{4}{n}$
This value is maximum for minimum value of $n$, which is $1.$
Therefore, $\lambda_{\max }=4$ meters
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1$25$ tunning forks are arranged in series in the order of decreasing frequency. Any two successive forks produce $3\, beats/sec.$ If the frequency of the first turning fork is the octave of the last fork, then the frequency of the $21^{st}$ fork is .... $Hz$View Solution
- 2A wave travelling in positive $x-$direction with $A = 0.2\;m$ has a velocity of $360 \;m/sec.$ if $\lambda = 60\;m,$ then correct expression for the wave isView Solution
- 3The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe $L$ metre long. The length of the open pipe will beView Solution
- 4View SolutionThe diagram below shows the propagation of a wave. Which points are in same phase
- 5An engine is moving on a circular track with a constant speed. It is blowing a whistle of frequency $500 Hz$. The frequency received by an observer standing stationary at the centre of the track isView Solution
- 6A tuning fork of known frequency $256\,Hz$ makes $5$ beats per second with the vibrating string of a guitar. The beat frequency decreases to $2$ beats per second when the tension in the guitar string slightly increased. The frequency of the guitar string before increasing the tension was ..... $Hz$View Solution
- 7The frequency of a sound wave is $n$ and its velocity is $v$. If the frequency is increased to $4n,$ the velocity of the wave will beView Solution
- 8A steel wire has a length of $12.0 \;m$ and a mass of $2.10 \;kg .$ What should be the tension in the wire so that speed of a transverse wave on the wire equals the speed of sound in dry air at $20\,^{\circ} C =343\; m s ^{-1}$View Solution
- 9Two uniform strings of mass per unit length $\mu$ and $4 \mu$, and length $L$ and $2 L$, respectively, are joined at point $O$, and tied at two fixed ends $P$ and $Q$, as shown in the figure. The strings are under a uniform tension $T$. If we define the frequency $v_0=\frac{1}{2 L} \sqrt{\frac{T}{\mu}}$, which of the following statement($s$) is(are) correct?View Solution
$(A)$ With a node at $O$, the minimum frequency of vibration of the composite string is $v_0$
$(B)$ With an antinode at $O$, the minimum frequency of vibration of the composite string is $2 v_0$
$(C)$ When the composite string vibrates at the minimum frequency with a node at $O$, it has $6$ nodes, including the end nodes
$(D)$ No vibrational mode with an antinode at $O$ is possible for the composite string
- 10View SolutionIn the musical octave ‘Sa’, ‘Re’, ‘Ga’