A piston of cross-section area $100\, cm^2$ is used in a hydraulic press to exert a force of $107\, dynes$ on the water. The cross-sectional area of the other piston which supports an object having a mass $2000 \,kg$. is
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(c) ${P_1} = {P_2} \Rightarrow \frac{{{F_1}}}{{{A_1}}} = \frac{{{F_2}}}{{{A_2}}}$==> $\frac{{{{10}^7}}}{{{{10}^2}}} = \frac{{2000 \times {{10}^3} \times {{10}^3}}}{{{A_2}}}$
$\therefore {A_2} = 2 \times {10^4}c{m^2}$$(g = 980 \approx {10^3}cm/{s^2})$
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