- A$\frac{{\Delta {S^o}}}{{2.303R}}$
- ✓$\frac{{\Delta {S^o}}}{R}$
- C$-\frac{{\Delta {S^o}}}{R}$
- D$R \times \Delta {S^o}$
$\ln K =\frac{\Delta S ^{\circ}}{ R }-\frac{\Delta H ^{\circ}}{ RT }$
Thus, a plot of $\ln K$ versus $1 / T$ (abscissa) will be straight line with slope equal to $-\frac{\Delta H ^{\circ}}{ R }$ and intercept $\frac{\Delta S ^{\circ}}{ R }$
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($i$) $P \xrightarrow[\text { ii) } \mathrm{Zn} / \mathrm{H}_2 \mathrm{O}]{\text { i) } \mathrm{O}_3 / \mathrm{CH}_2 \mathrm{Cl}_2} \underset{\left(\mathrm{C}_8 \mathrm{H}_8 \mathrm{O}\right)}{Q}$
($ii$) $R \xrightarrow[\text { ii) } \mathrm{Zn} / \mathrm{H}_2 \mathrm{O}]{\text { i) } \mathrm{O}_3 / \mathrm{CH}_2 \mathrm{Cl}_2} \underset{\left(\mathrm{C}_8 \mathrm{H}_8 \mathrm{O}\right)}{S}$
The option(s) with suitable combination of $P$ and $R$, respectively, is(are)
$(i)\, LiF > LiCl > LiBr > LiI$
$(ii)\, CaCl_2 < FeCl_2 < FeCl_3$
$(iii)Hg_2Cl_2 > HgCl_2$
$(iv)\, ZnCl_2 < CdCl_2 < HgCl_2$
$(v) CuCl < AgCl < AuCl$
$(vi) AlN > Al_2O_3 > AlF_3$
$(vii) CaF_2 < CaCl_2 < CaBr_2 < CaI_2$
