A proton moving with a constant velocity passes through a region of space without any change in its velocity. If $\overrightarrow E $ and $\overrightarrow B $ represent the electric and magnetic fields respectively, then this region of space may have
IIT 1985, Medium
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(d) Here the proton has no acceleration so $E = B = 0.$
When $E = 0$but $B \ne 0,$but parallel to the motion of proton, there will be no force acting.
When $E \ne 0$and $B \ne 0$ and $E$, $B$ and motion of proton $\left( v \right)$ are mutually perpendicular, there may be no net force. Forces due to $E$ and $B$ cancel each other.
When $E = 0$but $B \ne 0,$but parallel to the motion of proton, there will be no force acting.
When $E \ne 0$and $B \ne 0$ and $E$, $B$ and motion of proton $\left( v \right)$ are mutually perpendicular, there may be no net force. Forces due to $E$ and $B$ cancel each other.
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