A very long straight wire carries a current $I$. At the instant when a charge $ + Q$ at point $P$ has velocity $\overrightarrow V $, as shown, the force on the charge is
AOpposite to $OX$
BAlong $OX$
COpposite to $OY$
DAlong $OY$
AIPMT 2005, Easy
Download our app for free and get started
DAlong $OY$
d (d) Magnetic field produced by wire at the location of charge is perpendicular to the paper inwards. Hence by applying Fleming's left hand rule, force is directed along $OY$.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A coil having $100$ turns, area of $5 \times 10^{-3} \mathrm{~m}^2$, carrying current of $1 \mathrm{~mA}$ is placed in uniform magnetic field of $0.20 \mathrm{~T}$ such a way that plane of coil is perpendicular to the magnetic field. The work done in turning the coil through $90^{\circ}$ is . . . . . . $\mu \mathrm{J}$.
If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$. Then the total current I when its figure of merit is $K$ will be
A circular coil having $N\,turns$ and radius $r$ carries a current. It is held in the $XZ$ plane in a magnetic field $B\hat i$ . The torque on the coil due to the magnetic field is
A thin circular frame of radius $'a'$ is made of insulating material. A square loop is constructed with in it. If loop carrying current $I$ , then magnetic induction at geometrical centre $'O'$ will be
An electron moves through a uniform magnetic field $\vec{B}=B_0 \hat{i}+2 B_0 \hat{j} T$. At a particular instant of time, the velocity of electron is $\overrightarrow{\mathrm{u}}=3 \hat{i}+5 \hat{j} \mathrm{~m} / \mathrm{s}$. If the magnetic force acting on electron is $\overrightarrow{\mathrm{F}}=5 \mathrm{ekN}$, where $e$ is the charge of electron, then the value of $\mathrm{B}_0$ is ____$\mathrm{T}$.