A current $i$ is flowing in a conductor of length $l$. When it is bent in the form of a circular loop then its magnetic moment will be-
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$M=\mathrm{i} \mathrm{A}=\mathrm{i} \pi \mathrm{r}^{2}$
But $2 \pi r=1 \quad \therefore M=i \pi \frac{1^{2}}{4 \pi^{2}}=\frac{i l^{2}}{4 \pi}$
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