A rectangular block of mass $5\,kg$ attached to a horizontal spiral spring executes simple harmonic motion of amplitude $1\,m$ and time period $3.14\,s$. The maximum force exerted by spring on block is $.......N$.
JEE MAIN 2023, Medium
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$\therefore T =3.14=\pi$
$T =\pi=\frac{2 \pi}{\omega} \Rightarrow \omega=2$
$F _{\max }= ma _{\max }$
$= m \left( A \omega^2\right)$
$= mA (2)^2$
$=5 \times 1 \times 4$
$=20\,N$
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