In an elevator, a spring clock of time period $T_S$ (mass attached to a spring) and a pendulum clock of time period $T_P$ are kept. If the elevator accelerates upwards
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$T_{s}=2 \pi \sqrt{\frac{m}{k}} T_{s}$ doesn't depend on $g .$

$T_{p}=2 \pi \sqrt{\frac{\ell}{g}} ; \quad T_{p} \propto g^{-1 / 2}$

$\therefore T_{p}$ decreases

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