A rectangular coil $20\,cm \times 20\,cm$ has $100$ $turns$ and carries a current of $1\, A$. It is placed in a uniform magnetic field $B =0.5\, T$ with the direction of magnetic field parallel to the plane of the coil. The magnitude of the torque required to hold this coil in this position is........$N-m$
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(c) $\tau = NBiA = 100 \times 0.5 \times 1 \times 400 \times {10^{ - 4}} = 2\;N - m$
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