$\frac{2}{x}=\frac{\ell+0.2}{1-(\ell-0.2)}=\frac{\ell+0.2}{0.8-\ell}$

$\frac{\ell(\ell+0.2)}{(1-\ell)(0.8-\ell)}=1$

$\ell^{2}+0.2 \ell=0.8+\ell^{2}-0.8 \,\ell-\ell$

$2\, \ell=0.8$

$\ell=0.4 \mathrm{\,m}$

$\frac{x}{2}=\frac{0.4}{0.6} \Rightarrow x=\frac{4}{3}$

$\frac{2}{x}=\frac{\ell-0.2}{1-(\ell-0.2)}=\frac{\ell-0.2}{1.2-\ell}$

$1=\frac{\ell(\ell-0.2)}{(1-\ell)(1.2-\ell)}$

$\ell-0.2\, \ell=1.2+\ell^{2}-2.2\, \ell$

$2 \ell=1.2$

$\ell=0.6$

$\Rightarrow x=\frac{2 \times 0.6}{0.4}=3\, \Omega$