A rod of length $1.2\,m$ is clamped at the mid point and its fundamental frequency is $2\,MHz$ , then speed of wave inside the rod?
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$\mathrm{L}=\lambda / 2 \Rightarrow \lambda=2 \mathrm{L}$
$\mathrm{f}_{0}=\mathrm{v} / \lambda=\mathrm{v} / 2 \mathrm{L}$
$\mathrm{v}=2 \mathrm{L} \mathrm{f}_{0}$
$=2 \times 1.2 \times 2 \times 10^{6}$
$\mathrm{v}=4.8 \times 10^{6} \mathrm{\,m} / \mathrm{s}$
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