moles of $CH _{4}=$ moles of $ROH$
$\frac{ V }{22400}=\frac{ m }{ M \cdot M }$ (Assuming NTP Condition)
$\frac{3.1}{22400}=\frac{4.5 \times 10^{-3}}{ M.M }$
$MM =32.51$
Nearest Integer $=33$
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