MCQ
A sample of calcium carbonate $(CaC{O_3})$ has the following percentage composition : $Ca = 40\%$; $C = 12\%$; $O = 48\%$ If the law of constant proportions is true, then the weight of calcium in $4 \,g$ of a sample of calcium carbonate obtained from another source will be.....$g$
  • A
    $0.016$
  • B
    $0.16$
  • $1.6$
  • D
    $16$

Answer

Correct option: C.
$1.6$
c
In $100 \,g\, CaCO _3, 40 \,g\,Ca$ is present.

In $4 \,g\, CaCO _3$, Let $x \,g\,Ca$ be present

$\frac{ x }{4}=\frac{40}{100}$

$\Rightarrow x =1.6 \,g$

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