MCQ
A sample of calcium carbonate $(CaC{O_3})$ has the following percentage composition : $Ca = 40\%$; $C = 12\%$; $O = 48\%$ If the law of constant proportions is true, then the weight of calcium in $4 \,g$ of a sample of calcium carbonate obtained from another source will be.....$g$
- A$0.016$
- B$0.16$
- ✓$1.6$
- D$16$
