Question
A sample of HI(g) is placed in flask at a pressure of 0.2 atm. At equilibrium the
partial pressure of HI(g) is 0.04 atm.
What is $\text{K}_\text{p}$ for the given equilibrium?
$\text{2HI (g)}\rightleftharpoons\text{H}_2\text{ (g) + I}_2\text{ (g)}$

Answer

$\begin{matrix}&2\text{HI}_{\text{(g)}}&\rightleftharpoons&\text{H}_{2\text{(g)}}&+&\text{I}_{2\text{(g)}}\\\text{Initial pressure}&0.2\text{ atm}&&0&&0\\\text{Pressure at eqm.}&0.04\text{ atm}&&\frac{0.16}{2}&&\frac{0.16}{2}\\&&&=0.08\text{ atm}&&=0.08\text{ atm}\end{matrix}$
According to law of chemical equilibrium,
$\text{K}_{\text{p}}=\frac{\text{p}_{\text{H}_2}}{\text{p}^2_\text{HI}}=\frac{0.08\times0.08}{(0.04)^2}=\frac{0.0064}{0.0016}=4$
$\therefore\ \text{K}_{\text{p}}=4$

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