MCQ
A screw gauge gives the following readings when used to measure the diameter of a wire

Main scale reading : $0 \,\mathrm{~mm}$

Circular scale reading $: 52$ $divisions$

Given that $1\, \mathrm{~mm}$ on main scale corresponds to $100\, divisions$ on the circular scale. The diameter of the wire from the above data is ...... $cm$

  • A
    $0.52$
  • B
    $0.026$
  • C
    $0.26$
  • $0.052$

Answer

Correct option: D.
$0.052$
d
$L. C.$ $=\frac{\text { Pitch }}{C . S D}$

$=\frac{1 m m}{100}=0.01 \,\mathrm{~m}=0.001\, \mathrm{~cm}$

Radius $=\mathrm{M.S} .+\mathrm{n}(\mathrm{L}-\mathrm{I})$

$=0+52(0.001)$

$=0.052 \,\mathrm{~cm}$

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