MCQ
A simple pendulum is attached to a block which slides without friction down an inclined plane $A B C$ having an angle of inclination $\alpha$ as shown below. While the block is sliding down the pendulum oscillates in such a way that at its mean position the direction of the string is
  • A
    at angle $\alpha$ to the perpendicular to the inclined plane $A C$
  • B
    parallel to the inclined plane $A C$
  • C
    vertically downwards
  • perpendicular to the inclined plane $A C$

Answer

Correct option: D.
perpendicular to the inclined plane $A C$
d
(d)

As block slides down the plane, pendulum bob is subjected to two forces.

$(i)$ Weight mg perpendicularly downwards to the horizontal.

$(ii)$ Pesudo force $m g \sin \theta$ acting upwards and parallel to the inclined plane.

Resultant of these forces is perpendicular to inclined plane $A C$. So, mean position of pendulum is perpendicular to $A C$.

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