Question
A simple pendulum moves from one $\left(\frac{1}{2}\right)$ end to other in a second, what will be its frequency?
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Answer
Period T $=2 \times \frac{1}{2}$ second $=1$ second
Frequency $n=\frac{1}{T}=\frac{1}{1 sec }=1 sec ^{-1}$
Frequency $n=\frac{1}{T}=\frac{1}{1 sec }=1 sec ^{-1}$
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