A simple pendulum of mass $m$ executes $S.H.M.$ with total energy $E$. If at an instant it is at one of extreme positions, then its linear momentum after a phase shift of $\frac{\pi}{3} \,rad$ will be
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(b)
Energy $=E_0$
After a phase shift of $\frac{\pi}{3}$
$E=E_0 \cos ^2 \frac{\pi}{3}$
$\frac{P^2}{2 m}=\frac{E_0 3}{4}$
$P=\sqrt{\frac{3 m E}{2}}$
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