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A simple pendulum of mass $'m',$ length $'I'$ and charge $'+q'$ suspended in the electric field produced by two conducting parallel plates as shown. The value of deflection of pendulum in equilibrium position will be -
  • A$\tan ^{-1}\left[\frac{{q}}{{mg}} \times \frac{{C}_{2}\left({V}_{2}-{V}_{1}\right)}{\left({C}_{1}+{C}_{2}\right)({d}-{t})}\right]$
  • B$\tan ^{-1}\left[\frac{{q}}{{mg}} \times \frac{{C}_{1}\left({V}_{1}+{V}_{2}\right)}{\left({C}_{1}+{C}_{2}\right)({d}-{t})}\right]$
  • C$\tan ^{-1}\left[\frac{{q}}{m g} \times \frac{C_{1}\left(V_{2}-V_{1}\right)}{\left(C_{1}+C_{2}\right)(d-t)}\right]$
  • D$\tan ^{-1}\left[\frac{{q}}{{mg}} \times \frac{{C}_{2}\left({V}_{1}+{V}_{2}\right)}{\left({C}_{1}+{C}_{2}\right)({d}-{t})}\right]$
JEE MAIN 2021, Diffcult
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