A small block of mass $m$, having charge $q$ is placed on frictionless inclined plane making an angle $\theta$ with the horizontal. There exists a uniform magnetic field $B$ parallel to the inclined plane but perpendicular to the length of spring. If $m$ is slightly pulled on the inclined in downward direction and released, the time period of oscillation will be (assume that the block does not leave contact with the plane)
A$2\pi \sqrt {\frac{m}{k}}$
B$2\pi \sqrt {\frac{{2m}}{k}}$
C$2\pi \sqrt {\frac{{qB}}{K}}$
D$2\pi \sqrt {\frac{{qB}}{{2K}}}$
Medium
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A$2\pi \sqrt {\frac{m}{k}}$
a There will be no effect of magnetic force on time period because the magnetic force will be perpendicular to the inclined plane.
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