The maximum current that can be measured by a galvanometer of resistance $40 \,\Omega$ is $10\, mA$. It is converted into a voltmeter that can read upto $50\, V$. The resistance to be connected in series with the galvanometer is ... (in $ohm$)
  • A$5040$
  • B$4960$
  • C$2010$
  • D$4050$
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