Explanation:
Let $\theta$ be the inclination angle.
From the free body diagram, we have:
$\text{N}=\text{mg}\cos\theta\ \dots(\text{i})$
$\text{ma}=\text{mg}\sin\theta-\text{f}_{\text{r}}\ \dots(\text{ii})$
Putting $\text{f}_{\text{r}}=\mu\text{N}$ in (ii) we get,
$\text{a}=\text{g}(\sin\theta-\mu\cos\theta)$
The friction coefficients between the objects and the incline are same and not sufficient to allow pure rolling; therefore, all the bodies come down with the same acceleration.
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