MCQ
A solid sphere of mass $1\ kg$ rolls on a table with linear speed $1\ m/s$. Its total kinetic energy is .......... $J$
- A$1$
- B$0.5$
- ✓$0.7$
- D$1.4$
✓
Answer
Correct option: C.
$0.7$
c
$E=\frac{1}{2} M v^{2}+\frac{1}{2} I \omega^{2}$
$E=\frac{1}{2} M v^{2}+\frac{1}{2} I \omega^{2}$
$=\displaystyle \frac {1}{2}Mv^2$
$\displaystyle \frac {1}{2} \times \displaystyle \frac {2}{5}MR^2 \times \displaystyle \frac {V^2}{R^2}$
$=\displaystyle \frac {7}{10} Mv^2=0.7 \space J$
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