A solution contains $16\ g$ of urea in $120\ g$ of the solution. What is mass by mass percentage of solution?
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Mass of solute $= 16\ g$
Mass of solution $= 120\ g$ Mass $\%$
= mass of solute ÷ mass of solution $\times 100$
$= 16 ÷ 120 \times 100$
$ = 13.333333333...\% = 13 \%$ (approx)
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The teacher instructed three students $‘A’, ‘B’$ and $‘C’$ respectively to prepare a $50 \%$ (mass by volume) solution of sodium hydroxide $(NaOH)$. $‘A’$ dissolved $50g$ of $NaOH$ in $100\ mL$ of water, $‘B’$ dissolved $50\ g$ of $NaOH$ in $100\ g$ of water while $‘C’$ dissolved $50\ g$ of $NaOH$ in water to make $100\ mL$ of solution. Which one of them has made the desired solution and why?