(Given : Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ Ethyl alcohol : $46$,
water : $18$)
- A$20$
- ✓$22$
- C$30$
- D$35$
(Given : Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ Ethyl alcohol : $46$,
water : $18$)
$=\frac{\text { Mass of ethyl alcohol }}{\text { Total mass of solution }} \times 100$
$=\frac{1 \times 46}{1 \times 46+9 \times 18} \times 100=\frac{4600}{208}$
$=22.11 \text { Or } 22$
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$\mathop {Ph - OH}\limits_{(A)} ,\,\,\,\,\mathop {Ph - C{H_2} - OH}\limits_{(B)} ,\,\,\,\,\mathop {Ph - C{O_2}H}\limits_{(C)} ,\,\,\,\mathop {Ph - C{H_2}-\mathop N\limits^ \oplus {H_3}}\limits_{(D)} $
$Gas$ $(A)$ bums with a blue flame and is oxidised to $gas$ $(B)$,
$Gas\left( A \right) + C{l_2} \to \left( D \right)\xrightarrow{{N{H_3},\Delta }}\left( E \right)$.
$A,B, C$ and $E$ are

