MCQ
A solution is prepared by adding 1 mole ethyl alcohol in $9$ mole water. The mass percent of solute in the solution is. . . . . . . (Integer Answer)

(Given : Molar mass in $\mathrm{g} \mathrm{mol}^{-1}$ Ethyl alcohol : $46$,

water : $18$)

  • A
    $20$
  • $22$
  • C
    $30$
  • D
    $35$

Answer

Correct option: B.
$22$
b
$\text { Mass percent of Alcohol }$

$=\frac{\text { Mass of ethyl alcohol }}{\text { Total mass of solution }} \times 100$

$=\frac{1 \times 46}{1 \times 46+9 \times 18} \times 100=\frac{4600}{208}$

$=22.11 \text { Or } 22$

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