A solution of alcohol in water has been prepared by mixing $150\ mL$ of alcohol with $600\ mL$ of water. Calculate the volume percentage of the solution.
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Percentage concentration $=\frac{\text{Volume of solute}}{\text{Volume of solution}}\times100\%$
$=\frac{150\text{ml(slovent)}}{750\text{ml(solution)}}\times100\%=\frac{15000}{750}$
Percentage concentration $= 20 \%$
$=\frac{150\text{ml(slovent)}}{750\text{ml(solution)}}\times100\%=\frac{15000}{750}$
Percentage concentration $= 20 \%$
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