MCQ
A solution of $\mathrm{H}_2 \mathrm{SO}_4$ is $31.4 \% \mathrm{H}_2 \mathrm{SO}_4$ by mass and has a density of $1.25 \mathrm{~g} / \mathrm{mL}$. The molarity of the $\mathrm{H}_2 \mathrm{SO}_4$ solution is _____________$\quad \mathrm{M}$ (nearest integer)[Given molar mass of $\mathrm{H}_2 \mathrm{SO}_4=98 \mathrm{~g} \mathrm{~mol}^{-1}$ ]
  • $4$
  • B
    $3$
  • C
    $2$
  • D
    $1$

Answer

Correct option: A.
$4$
a
$ \mathrm{M}=\frac{\mathrm{n}_{\text {solute }}}{\mathrm{V}} \times 1000 $

$ =\frac{\left(\frac{31.4}{98}\right)}{\left(\frac{100}{1.25}\right)} \times 1000 $

$ =4.005 \approx 4$

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