Question
A source of sound with adjustable frequency produces $2$ beats per second with a tuning fork when its frequency is either $476\ Hz$ or $480\ Hz.$ What is the frequency of the tuning fork?

Answer

Given, First Frequency $f_1 = 476\ Hz$ Second frequency $f_2 = 480\ Hz$
Number of beats produced per second by the tuning fork $m = 2$
As the tuning fork produces $2$ beats, its frequency should be an average of two.
This is given by,$\text{f}=\frac{(\text{f}_1+\text{f}_2)}{2}$
$\text{f}=\frac{(476+480)}{2}$
$=478\ \text{Hz}$

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