A source voltage of $8 V$ drives the diode in fig. through a currentlimiting resistor of $100 ohm$. Then the magnitude of the slope load line on the $V-I$ characteristics of the diode is
A$0.01$
B$100$
C$0.08$
D$12.5$
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A$0.01$
If $i$ is the current in the diode and $V$ is voltage drop across it, then for given figure voltage equation is$i \times 100+V=8 \Rightarrow i=-\frac{1}{100} V+\frac{8}{100} $
$\Rightarrow i=-(0.01) V+0.08$
Thus the slope of $i$ - $V$ graph $=\frac{1}{R_L}=0.01$
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