Two capacitors $C_1$ and $C_2$ are charged to $120\ V$ and $200\ V$ respectively. It is found that connecting them together the potential on each one can be made zero. Then
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In a medium of dielectric constant $K$, the electric field is $\vec E$ . If ${ \varepsilon _0}$ is permittivity of the free space, the electric displacement vector is
From a supply of identical capacitors rated $8\ \mu F$, $250\ V$, the minimum number of capacitors required to form a composite $16$ $\mu F$, $1000$ $V$ is :
Five identical plates each of area $A$ are joined as shown in the figure. The distance between the plates is $d$. The plates are connected to a potential difference of $V\;volts$. The charge on plates $1$ and $4$ will be
A particle $A$ has charge $+q$ and particle $B$ has charge $+4 q$ with each of them having the same mass $m$. When allowed to fall from rest through the same electric potential difference, the ratio of their speeds $\frac{V_A}{V_B}$ will become
As shown in the figure, two parallel plate capacitors having equal plate area of $200\,cm ^2$ are joined in such a way that $a \neq b$. The equivalent capacitance of the combination is $x \varepsilon_0 F$. The value of $x$ is $..........$.
Five capacitors together with their capacitances are shown in the adjoining figure. The potential difference between the points $A$ and $B$ is $60\, volt$. The equivalent capacitance between the point $A$ and $B$ and charge on capacitor $5 \mu F$ will be respectively:-
The potential at a point $P$ due to an electric dipole is $1.8\times 10^5\,V$ . If $P$ is at a distance of $50\,cm$ apart from the centre $O$ of the dipole and if $CP$ makes an angle $60^o$ with the positive side of the axial line of the dipole, what is the moment of the dipole?
A parallel plate capacitor is charged to a potential difference of $100\,V$ and disconnected from the source of $emf$ . A slab of dielectric is then inserted between the plates. Which of the following three quantities change?