A sphere of solid material of relative density 9 has a concentric spherical cavity and floats having just sinked in water. If the radius of

Q: A sphere of solid material of relative density $9$ has a concentric spherical cavity and floats having just sinked in water. If the radius of the sphere be $R$, then the radius of the cavity $(r)$ will be related to $R$ as :-

a $\frac{4}{3} \pi\left(\mathrm{R}^{3}-\mathrm{r}^{3}\right) \rho \mathrm{g}=\frac{4}{3} \pi \mathrm{R}^{3} \rho_{\mathrm{w}} \mathrm{g}$ $9\left(R^{3}-r^{3}\right)=R^{3}$ $r^{3}=\frac{8 R^{3}}{9}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A sphere of solid material of relative density $9$ has a concentric spherical cavity and floats having just sinked in water. If the radius of the sphere be $R$, then the radius of the cavity $(r)$ will be related to $R$ as :-

A$r^3 = \frac{8}{9} R^3$
B$r^3 = \frac{2}{3} R^3$
C$r^3 = \frac{\sqrt 8}{3} R^3$
D$r^3 = \sqrt { \frac{2}{3}} R^3$

Diffcult

STD 11 Science
NEET
STD 11 - 9.1. fluid mechanics
Physics

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