A spherical mirror produces an image of magnification -1.0 on a screen placed at a distance of 30 cm from the pole of the mirror.
  1. Write the type of mirror in this case.
  2. What is the focal length of the mirror?
  3. What is the nature of the image formed?
  4. Draw the ray diagram to show the image formation in this case.
CBSE DELHI - SET 3 2014
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  • Spherical mirror.
  • Magnification, m = -1
  • image is formed on the screen.
Therefore image is real.
  • image distance, v = -30 cm (-ve sign for real image)
  1. Concave mirror.
  2. $f = ?$
$\frac{-v}{u}$ $\Rightarrow$ $\frac{-(-30)}{u} = -1$
$\Rightarrow 30 = -u$ $\therefore$ $u = -30 \text{ cm}$
$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$ $\Rightarrow$ $\frac{1}{f} = \frac{1}{-30} + \frac{1}{-30}$
$\frac{1}{f} = -\frac{1}{30} - \frac{1}{30} = \frac{-2}{30} = \frac{-1}{15}$ $\therefore$ $f = -15 \text{ cm}$
  1. Image is real, inverted and same size of the object.
  2.  
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