MCQ
A spring with spring constant $k $  is extended from $x = 0$to$x = {x_1}$. The work done will be
  • A
    $kx_1^2$
  • $\frac{1}{2}kx_1^2$
  • C
    $2kx_1^2$
  • D
    $2k{x_1}$

Answer

Correct option: B.
$\frac{1}{2}kx_1^2$
b
(b) $F=-k x$

$d w=F \cdot d x$

$\int d x=\int_{0}^{x_1}-k x d x$

$w=-k \int_{0}^{x_1}xdx$

$=-k\left[\frac{x^{2}}{2}\right]_{0}^{x_{1}}$

$=-K\left[\frac{x_{1}^{2}}{2}\right]$

$w=-\frac{-k x_{1}^{2}}{2}$

$w=\frac{-1}{2} k x_{1}^{2}$

work  done $=-(w)$

$=-\left[\frac{-1}{2} k x_{1}^{2}\right]$

$=\frac{1}{2} k x_{1}^{2}$

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