MCQ
A spring with spring constant k when stretched through $1\, cm$, the potential energy is $U$. If it is stretched by $4 \,cm.$ The potential energy will be
- A$4U$
- B$8U$
- ✓$16 U$
- D$2U$
✓
Answer
Correct option: C.
$16 U$
c
(c)Potential energy $U = \frac{1}{2}k{x^2}$
$U \propto {x^2}$[if k = constant]
If elongation made $4$ times then potential energy will become $16\, times$.
(c)Potential energy $U = \frac{1}{2}k{x^2}$
$U \propto {x^2}$[if k = constant]
If elongation made $4$ times then potential energy will become $16\, times$.
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