Given speed of sound,
$v=300 \,ms ^{-1}$
And wave equation is
$y=y_0 \sin \left(\frac{2 \pi}{L} x\right) \cdot \sin \left(\frac{2 \pi}{L} x+\frac{\pi}{4}\right)$
So, angular wave number,
$k=\frac{2 \pi}{\lambda}=\frac{2 \pi}{L}$
$\therefore \quad \lambda=L=1.2 \,m$
Frequency of fundamental vibration is
$v=\frac{v}{\lambda}=\frac{300}{12}=250 \,Hz$
So, option $(d)$ is incorrect.
where $x$ and $y$ are in metres and $t$ is in seconds. The ratio of maximum particle velocity to the wave velocity is
| List $-I$ | List $-II$ |
| $(I)$ String $-1( \mu$ ) | $(P) 1$ |
| $(II)$ String $-2 (2 \mu)$ | $(Q)$ $1 / 2$ |
| $(III)$ String $-3 (3 \mu)$ | $(R)$ $1 / \sqrt{2}$ |
| $(IV)$ String $-4 (4 \mu)$ | $(S)$ $1 / \sqrt{3}$ |
| $(T)$ $3 / 16$ | |
| $(U)$ $1 / 16$ |