- AThe pipe is closed at both ends
- BThe wavelength of the wave could be $1.2 ]\,m$
- CThere could be a node at $x=0$ and antinode at $x=L / 2$
- ✓The frequency of the fundamental mode of vibrations is $137.5 \,Hz$
Given speed of sound,
$v=300 \,ms ^{-1}$
And wave equation is
$y=y_0 \sin \left(\frac{2 \pi}{L} x\right) \cdot \sin \left(\frac{2 \pi}{L} x+\frac{\pi}{4}\right)$
So, angular wave number,
$k=\frac{2 \pi}{\lambda}=\frac{2 \pi}{L}$
$\therefore \quad \lambda=L=1.2 \,m$
Frequency of fundamental vibration is
$v=\frac{v}{\lambda}=\frac{300}{12}=250 \,Hz$
So, option $(d)$ is incorrect.
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Statement $I$ : When speed of liquid is zero everywhere, pressure difference at any two points depends on equation $\mathrm{P}_1-\mathrm{P}_2=\rho \mathrm{g}\left(\mathrm{h}_2-\mathrm{h}_1\right)$
Statement $II$ : In ventury tube shown $2 \mathrm{gh}=v_1^2-v_2^2$
In the light of the above statements, choose the most appropriate answer from the options given below.
