d
Writing force equation in vertical direction
${Mg}-{N}={Ma}$
$\Rightarrow 70 {g}-{N}=70 \times 0.2$
$\Rightarrow {N}=70[\,{g}-0.2]=70 \times 9.8$
$\therefore {N}=686\, \text { Newton }$
Note : Since there is no compressive normal from the sides, hence friction will not act.
