A car having a mass of $1000\, kg$ is moving at a speed of $30\, metres/sec$. Brakes are applied to bring the car to rest. If the frictional force between the tyres and the road surface is $5000$ newtons, the car will come to rest in ........ $\sec$
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(d) $v = u - at \Rightarrow \;t = \frac{u}{a}$ [As $v = 0$]
$t = \frac{{u \times m}}{F}$$ = \frac{{30 \times 1000}}{{5000}} = 6\;\sec $
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