Hence, fundamental frequency of vibrating rod is given by ${n_1} = \frac{v}{{2l}}$
==> $2.53 = \frac{v}{{4 \times 1}}$
==> $v = 5.06 km/sec.$
$y(x,t)\, = \,0.6\,\sin \,\left( {\frac{{2\pi }}{3}x} \right)\,\cos \,(120\,\pi t)$
where $x$ and $y$ are in $metre$ and $t$ in $second$ . The length of the string is $1.5\,m$ and its mass is $3.0\times 10^{-2}\,kg$ the tension in the string will be .... $N$