A straight wire $AB$ of mass $40\,g$ and length $50\,cm$ is suspended by a pair of flexible leads in uniform magnetic field of magnitude $0.40\,T$ as shown in the figure. The magnitude of the current required in the wire to remove the tension in the supporting leads is ...........$A$. (Take $g=10\,ms ^{-2}$ ).
JEE MAIN 2023, Medium
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For equilibrium

$Mg = I \ell B$

$I =\frac{ mg }{\ell B }=\frac{40 \times 10^{-3} \times 10}{50 \times 10^{-2} \times 0.4}=2\,A$

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