A wire of length $314\,cm$ carrying current of $14\,A$ is bent to form a circle. The magnetic moment of the coil is $........A- m ^{2}$. [Given $\left.\pi=3.14\right]$
JEE MAIN 2022, Medium
Download our app for free and get started
$\frac{314}{100}=2 \pi R \quad R =0.5 m$
$\text { Magnetic Moment }= IA$
$=14 \times \pi R ^{2}$
$= 14 \times(3.14) \times \frac{1}{4}$3
$=10.99 \approx 11.00$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A square loop of edge length $2 \mathrm{~m}$ carrying current of $2 \mathrm{~A}$ is placed with its edges parallel to the $\mathrm{x}-\mathrm{y}$ axis. A magnetic field is passing through the $x-y$ plane and expressed as $\vec{B}=B_0(1+4 x) \hat{k}$, where $\mathrm{B}_0=5 \mathrm{~T}$. The net magnetic force experienced by the loop is. . . . . . . $\mathrm{N}$.View Solution
- 2A galvanometer gives full scale reading of $50\ mA$ , when a $p.d.$ , across its terminals is $0.15\ V$ . It can be used as an ammeter of range $0 - 100\ A$ by connecting a shunt resistance ofView Solution
- 3A horizontal rod of mass $10\, gm$ and length $10\, cm$ is placed on a smooth plane inclined at an angle of $60^\circ $ with the horizontal, with the length of the rod parallel to the edge of the inclined plane. A uniform magnetic field of induction $B$ is applied vertically downwards. If the current through the rod is $1.73$ $ampere$, then the value of $B$ for which the rod remains stationary on the inclined plane is......$Tesla$View Solution
- 4Two identical conducting wires $AOB$ and $COD$ are placed at right angles to each other. The wire $AOB$ carries an electric current $I_1$ and $COD$ carries a current $I_2$ . The magnetic field on a point lying at a distance $d$ from $O$, in a direction perpendicular to the plane of the wires $AOB$ and $COD$, will be given byView Solution
- 5A current $i$ is flowing in a conductor of length $l$. When it is bent in the form of a circular loop then its magnetic moment will be-View Solution
- 6Two galvanometers $A$ and $B$ require $3\,mA$ and $5\,mA$ respectively to produce the same deflection of $10$ divisions. ThenView Solution
- 7A straight conductor carrying current $i$ splits into two parts as shown in the figure. The radius of the circular loop is $R$. The total magnetic field at the centre $P$ of the loop isView Solution
- 8An ammeter whose resistance is $180\,\Omega $ gives full scale deflection when current is $2\, mA$. The shunt required to convert it into an ammeter reading $20\, mA$ (in $ohms$) isView Solution
- 9A closed loop $PQRS$ carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments $PS, SR$ and $RQ$ are $F_1, F_2$ and $F_3$ respectively and are in the plane of the paper and along the directions shown, the force on the segment $QP$ isView Solution
- 10A rectangular coil $20\,cm \times 20\,cm$ has $100$ $turns$ and carries a current of $1\, A$. It is placed in a uniform magnetic field $B =0.5\, T$ with the direction of magnetic field parallel to the plane of the coil. The magnitude of the torque required to hold this coil in this position is........$N-m$View Solution